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5t+2t^2=81
We move all terms to the left:
5t+2t^2-(81)=0
a = 2; b = 5; c = -81;
Δ = b2-4ac
Δ = 52-4·2·(-81)
Δ = 673
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{673}}{2*2}=\frac{-5-\sqrt{673}}{4} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{673}}{2*2}=\frac{-5+\sqrt{673}}{4} $
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